Investigating the Resistance of Wires :: Papers

Investigating the Resistance of Wires strike To investigate how the diameter of a constantan wire will tint its resistance and hence the flowing flowing through it. Prediction I predict that the thicker the diameter the less resistance there will be. ground In a metal, some of the electrons argon free to move betwixt the ions, to form a sea of electrons around the positive metal ions. Metals that are good conductors have more free electrons and therefore these electrons move advantageously around the positive metal ions. However in metals that have few free electrons, the ions act as obstacles to the flow of electrons and therefore the wire has resistance. The current becomes stronger with the more electrons that flow through a wire in angiotensin-converting enzyme second. As the diameter increases the electrons will have more available routes in the midst of the ions to pass through per second, making the electron flow greater hence the cu rrent becoming stronger. See figures 1 and 2 IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGE In a larger diameter, there IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEFigure 1 are more routes for free IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGE electrons to break IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGE through. IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGE In a smaller diameter, IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEFigure 2 there are fewer routes IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGE for the free electrons IMAGE to travel through. Plan I will set up a circuit consisting of a cell, ammeter, voltmeter and 50cm of constantan wire. The diameters I will wasting disease are as follows. 0.56m m, 0.43mm, 0.38mm, 0.32mm, 0.27mm and 0.20mm. I will measure these diameters with a micrometer. I will take three readings of the current and potential fight for individually different diameter of the wire and take an average for V (potential difference measured by a voltmeter) and I (current measured by an ammeter) in order to get the most accurate results possible. I will thus plot these results in two graphs one plotting V against I and some other plotting the average resistance (using ohms law R=V/I) against the diameter.